Would a time-dependent gravitational force be conservative?

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Time-Dependent Gravitational Forces: Conservative Nature Analysis

Time-Dependent Gravitational Forces and Their Conservative Nature

1. Fundamental Concepts of Conservative Forces

A force \(\mathbf{F}\) is conservative if it satisfies any of these equivalent conditions:

\[ \text{(1) } \oint_C \mathbf{F} \cdot d\mathbf{r} = 0 \quad \text{for any closed path } C \] \[ \text{(2) } W_{A→B} \text{ is path-independent} \] \[ \text{(3) } \exists U(\mathbf{r}) \text{ such that } \mathbf{F} = -\nabla U \] \[ \text{(4) } \nabla \times \mathbf{F} = 0 \text{ (irrotational)} \]

2. Time-Independent Gravitational Force

The classical Newtonian gravitational force between masses \(M\) and \(m\):

\[ \mathbf{F}(\mathbf{r}) = -G \frac{M m}{r^2} \hat{\mathbf{r}} \]

This derives from the potential energy function:

\[ U(r) = -G \frac{M m}{r} \]

Proof of Conservativeness

Calculating the curl in spherical coordinates:

\[ \nabla \times \mathbf{F} = \frac{1}{r^2 \sin\theta} \begin{vmatrix} \hat{r} & r\hat{\theta} & r\sin\theta\hat{\phi} \\ \frac{\partial}{\partial r} & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial \phi} \\ F_r & rF_\theta & r\sin\theta F_\phi \end{vmatrix} = 0 \]

Since \(F_\theta = F_\phi = 0\) and \(F_r\) depends only on \(r\), all terms vanish.

3. Time-Dependent Gravitational Force

Consider three cases of time dependence:

Case 1: Time-Varying Mass

\[ M(t) = M_0 e^{-\lambda t} \Rightarrow \mathbf{F}(\mathbf{r},t) = -G \frac{M_0 m e^{-\lambda t}}{r^2} \hat{r} \]

Case 2: Time-Varying Gravitational Constant

\[ G(t) = G_0 (1 + \alpha t) \Rightarrow \mathbf{F}(\mathbf{r},t) = -G_0(1+\alpha t) \frac{M m}{r^2} \hat{r} \]

Case 3: Moving Source Mass

\[ \mathbf{r}_s(t) \Rightarrow \mathbf{F}(\mathbf{r},t) = -G \frac{M m}{|\mathbf{r}-\mathbf{r}_s(t)|^3}(\mathbf{r}-\mathbf{r}_s(t)) \]

4. Work Calculation and Path Dependence

For time-dependent forces, the work integral becomes:

\[ W = \int_{t_A}^{t_B} \mathbf{F}(\mathbf{r}(t),t) \cdot \frac{d\mathbf{r}}{dt} dt \]

Explicit Time Dependence Example

For \(M(t) = M_0 e^{-\lambda t}\) along radial path \(r(t)\):

\[ W = -G M_0 m \int_{t_A}^{t_B} \frac{e^{-\lambda t}}{r(t)^2} \frac{dr}{dt} dt \]

Compare two paths from \(r_A\) to \(r_B\):

  1. Fast path: \(Δt → 0 \Rightarrow W ≈ -G M_0 m e^{-\lambda t_A} \left(\frac{1}{r_B} – \frac{1}{r_A}\right)\)
  2. Slow path: Significant mass loss during traversal ⇒ Different work

5. Mathematical Analysis

General Condition for Time-Dependent Forces

Even if \(\nabla \times \mathbf{F}(\mathbf{r},t) = 0\) instantaneously:

\[ \frac{dE}{dt} = \frac{\partial}{\partial t} U(\mathbf{r},t) \neq 0 \]

The total energy derivative:

\[ \frac{d}{dt}\left(\frac{1}{2}mv^2 + U(\mathbf{r},t)\right) = \frac{\partial U}{\partial t} \]

Potential Formulation Attempt

For \(\mathbf{F}(\mathbf{r},t) = -\nabla U(\mathbf{r},t)\):

\[ W = \int_\Gamma -\nabla U \cdot d\mathbf{r} = U(\mathbf{r}_A,t_A) – U(\mathbf{r}_B,t_B) + \int_{t_A}^{t_B} \frac{\partial U}{\partial t} dt \]

The additional time integral makes \(W\) path-dependent in spacetime.

Conclusion: Non-Conservative Nature of Time-Dependent Gravity

A time-dependent gravitational force fails to be conservative because:

  1. Path dependence: Work integral depends on the traversal history through the \(\frac{\partial U}{\partial t}\) term
  2. Energy non-conservation: \(\frac{dE}{dt} \neq 0\) due to explicit time dependence
  3. Spacetime coupling: The work done becomes a functional of both spatial path \(r(t)\) and time evolution

This has important physical consequences:

\[ \begin{cases} \text{Dissipation effects} \\ \text{No well-defined potential energy} \\ \text{Energy exchange with external systems} \end{cases} \]

6. Physical Implications

Astrophysical Examples

  • Mass-losing stars (\(Ṁ \neq 0\)) create non-conservative gravitational fields
  • Cosmological models with varying \(G(t)\) require modified energy accounting
  • Binary systems with gravitational wave emission exhibit effective time-dependent potentials

Mathematical Physics Perspective

The breakdown of conservativeness reflects:

\[ \frac{\partial \mathcal{L}}{\partial t} \neq 0 \Rightarrow \text{Noether’s theorem violation for time translation symmetry} \]

where \(\mathcal{L}\) is the Lagrangian of the system.

Time-Dependent Gravitational Forces

Time-Dependent Gravitational Forces and Conservative Nature

1. Introduction to Conservative Forces

A force \(\mathbf{F}\) is said to be conservative if:

\[ \oint \mathbf{F} \cdot d\mathbf{r} = 0 \]

Equivalently, it can be expressed as the negative gradient of a scalar potential:

\[ \mathbf{F} = -\nabla U \]

This implies the force is irrotational:

\[ \nabla \times \mathbf{F} = 0 \]

2. Time-Independent Conservative Forces

The gravitational force between masses \(M\) and \(m\):

\[ \mathbf{F}(\mathbf{r}) = -G \frac{M m}{r^2} \hat{\mathbf{r}} \]

Derived from potential energy:

\[ U(r) = -G \frac{M m}{r} \]

Taking the gradient confirms the relationship:

\[ \mathbf{F} = -\nabla U = -\frac{d}{dr}\left(-G \frac{M m}{r}\right) \hat{\mathbf{r}} = -G \frac{M m}{r^2} \hat{\mathbf{r}} \]

Since \(\nabla \times \mathbf{F} = 0\), the force is conservative.

3. Time-Dependent Forces

Consider a gravitational force with time-dependent parameters:

\[ \mathbf{F}(\mathbf{r}, t) = -G(t) \frac{M(t) m}{r^2} \hat{\mathbf{r}} \]

Possible scenarios include:

  • Mass \(M(t)\) changing over time (e.g., star losing mass)
  • Gravitational constant \(G(t)\) varying (cosmological models)

4. Work Done by a Time-Dependent Force

The work integral becomes:

\[ W = \int_\Gamma \mathbf{F}(\mathbf{r}, t) \cdot d\mathbf{r} \]

For time-dependent forces, \(W\) depends on both the path and traversal time.

Example: Exponentially Decaying Mass

For \(M(t) = M_0 e^{-\lambda t}\):

\[ \mathbf{F}(\mathbf{r}, t) = -G \frac{M_0 m e^{-\lambda t}}{r^2} \hat{\mathbf{r}} \]

Fast traversal approximation:

\[ W_{\text{fast}} \approx -G M_0 m e^{-\lambda t_A} \left( \frac{1}{r_B} – \frac{1}{r_A} \right) \]

Slow traversal exact form:

\[ W_{\text{slow}} = -G M_0 m \int_{t_A}^{t_B} \frac{e^{-\lambda t}}{r(t)^2} \frac{dr}{dt} dt \]

This demonstrates path-dependence in spacetime.

5. Mathematical Conditions

For time-dependent forces:

\[ \nabla \times \mathbf{F}(\mathbf{r}, t) = 0 \quad \forall t \]

is necessary but not sufficient for conservativeness.

Potential Energy Attempt

For \(\mathbf{F}(\mathbf{r}, t) = -\nabla U(\mathbf{r}, t)\):

\[ W = \int_\Gamma -\nabla U \cdot d\mathbf{r} = -\int_\Gamma \left( \frac{\partial U}{\partial x} dx + \frac{\partial U}{\partial y} dy + \frac{\partial U}{\partial z} dz \right) \]

The integral depends on time evolution along \(\Gamma\).

6. Energy Considerations

For time-dependent forces:

\[ \frac{dE}{dt} = \frac{d}{dt} \left( \frac{1}{2} m v^2 + U(\mathbf{r}, t) \right) = \mathbf{F} \cdot \mathbf{v} + \frac{\partial U}{\partial t} \]

If \(\mathbf{F} = -\nabla U\):

\[ \frac{dE}{dt} = \frac{\partial U}{\partial t} \neq 0 \]

Energy is not conserved unless \(\partial U/\partial t = 0\).

7. Conclusion

A time-dependent gravitational force is not conservative because:

  1. Work done depends on traversal time (path-dependence in spacetime)
  2. Mechanical energy is not conserved (\(\frac{dE}{dt} \neq 0\))
  3. Instantaneous irrotational condition (\(\nabla \times \mathbf{F} = 0\)) is insufficient

This leads to dissipation-like behavior, breaking the fundamental conservation properties of conservative forces.

Another Look:

Time-Dependent Gravitational Forces

Time-Dependent Gravitational Forces and Conservative Nature

1. Introduction to Conservative Forces

A force \( \mathbf{F} \) is called conservative if the work done around any closed path is zero:

\[ \oint \mathbf{F} \cdot d\mathbf{r} = 0 \]

Equivalently, it can be written as the negative gradient of a potential:

\[ \mathbf{F} = -\nabla U \]

This implies that the curl vanishes:

\[ \nabla \times \mathbf{F} = 0 \]

2. Time-Independent Gravitational Force

The classical Newtonian gravitational force:

\[ \mathbf{F}(\mathbf{r}) = -G \frac{M m}{r^2} \hat{\mathbf{r}} \]

Derived from the potential:

\[ U(r) = -G \frac{M m}{r} \]

The gradient check confirms it’s conservative:

\[ \mathbf{F} = -\nabla U = -\frac{d}{dr}\left(-G \frac{M m}{r}\right) \hat{\mathbf{r}} = -G \frac{M m}{r^2} \hat{\mathbf{r}} \]

3. Time-Dependent Gravitational Forces

Suppose we introduce time-varying parameters in gravity:

\[ \mathbf{F}(\mathbf{r}, t) = -G(t) \frac{M(t) m}{r^2} \hat{\mathbf{r}} \]

Scenarios include:

  • Changing mass \( M(t) \) (e.g., stars emitting solar winds)
  • Varying gravitational constant \( G(t) \) (e.g., cosmological theories)

4. Work Done in a Time-Dependent Field

The path integral of the force becomes time-sensitive:

\[ W = \int_\Gamma \mathbf{F}(\mathbf{r}, t) \cdot d\mathbf{r} \]

Work done now depends not just on the path but how fast it’s traversed.

Example: Exponentially Decaying Mass

If the mass of the source changes as \( M(t) = M_0 e^{-\lambda t} \):

\[ \mathbf{F}(\mathbf{r}, t) = -G \frac{M_0 m e^{-\lambda t}}{r^2} \hat{\mathbf{r}} \]

Fast Traversal:

\[ W_{\text{fast}} \approx -G M_0 m e^{-\lambda t_A} \left( \frac{1}{r_B} – \frac{1}{r_A} \right) \]

Slow Traversal (accurate):

\[ W_{\text{slow}} = -G M_0 m \int_{t_A}^{t_B} \frac{e^{-\lambda t}}{r(t)^2} \frac{dr}{dt} dt \]

This shows that the work depends on time and trajectory — a violation of conservativeness.

5. Mathematical Considerations

Even if:

\[ \nabla \times \mathbf{F}(\mathbf{r}, t) = 0 \quad \forall t \]

This alone doesn’t imply conservativeness when time is involved.

Potential Attempt:

If \( \mathbf{F}(\mathbf{r}, t) = -\nabla U(\mathbf{r}, t) \):

\[ W = -\int_\Gamma \nabla U(\mathbf{r}, t) \cdot d\mathbf{r} \]

Then using the chain rule:

\[ \frac{dU}{dt} = \frac{\partial U}{\partial t} + \nabla U \cdot \frac{d\mathbf{r}}{dt} \Rightarrow \nabla U \cdot \dot{\mathbf{r}} = \frac{dU}{dt} – \frac{\partial U}{\partial t} \]

Thus:

\[ W = -\Delta U + \int_{t_1}^{t_2} \frac{\partial U}{\partial t} dt \]

If \( \frac{\partial U}{\partial t} \neq 0 \), the force is not conservative.

6. Energy Considerations

Let total mechanical energy be:

\[ E = \frac{1}{2} m v^2 + U(\mathbf{r}, t) \]

Then:

\[ \frac{dE}{dt} = \frac{d}{dt} \left( \frac{1}{2} m v^2 \right) + \frac{\partial U}{\partial t} = \mathbf{F} \cdot \mathbf{v} + \frac{\partial U}{\partial t} \]

If \( \mathbf{F} = -\nabla U \), then:

\[ \frac{dE}{dt} = \frac{\partial U}{\partial t} \]

So unless \( \partial U / \partial t = 0 \), energy is not conserved — a hallmark of non-conservativeness.

7. Conclusion

A gravitational force that varies with time is not conservative because:

  1. Work done depends on traversal time and path in spacetime.
  2. Energy is not conserved due to explicit time-dependence of potential.
  3. Vanishing curl (\( \nabla \times \mathbf{F} = 0 \)) is insufficient when \( \mathbf{F} \) depends on \( t \).

In such systems, conservation of mechanical energy breaks down, and gravitational behavior mimics dissipative systems.

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