Ch1 Ex 1c Q12 A cheetah is pursuing an impala …

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The Problem:

A cheetah is pursuing an impala. The impala is running in a straight line at a constant speed of 16 m/s. The cheetah is 10 m behind the impala, running at 20 m/s but tiring, so that it is decelerating at 1 ms -2. Find an expression for the gap between the cheetah and the impala t seconds later. Will the impala get away?

Douglas Quadling Mechanics1 Exercise1C Q12

A cheetah is pursuing an impala. The impala is running in a straight line at a constant speed of 16 m/s. The cheetah is 10 m behind the impala, running at 20 m/s but tiring, so that it is decelerating at 1 m/s². Find an expression for the gap between the cheetah and the impala t seconds later. Will the impala get away?

Solution:

Step 1: Position of the Impala

The impala is moving at a constant speed, so its position at time t is:

x_i(t) = 16t

Step 2: Position of the Cheetah

The cheetah is decelerating, so its position at time t is:

x_c(t) = -10 + 20t - (1/2) t²

Step 3: Gap Between the Cheetah and the Impala

The gap at time t is:

G(t) = x_i(t) - x_c(t)

Substitute the expressions for x_i(t) and x_c(t):

G(t) = 16t - (-10 + 20t - (1/2) t²)

Simplify:

G(t) = (1/2) t² - 4t + 10

Step 4: Will the Impala Escape?

The gap G(t) is a quadratic function that opens upwards (since the coefficient of is positive). This means the gap will increase indefinitely over time, and the impala will escape.

Final Answer:

  1. Expression for the gap: G(t) = (1/2) t² - 4t + 10
  2. Will the impala escape? Yes, the impala will escape.
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