Ch1 Misc Ex1 Q5 The figure shows the (t,v) graph for the motion of a cyclist

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The Problem:


Douglas Quadling Mechanics1 Miscellaneous Exercise1 Q5

The figure shows the (t,v) graph for the motion of a cyclist; the graph consists of three straight line segments…….

Douglas Quadling Mechanics1 Miscellaneous Exercise1 Q5 The figure shows the (t,v) graph for the motion of a cyclist; the graph consists of three straight line segments.

:

Total Distance Calculation

The total distance traveled by the cyclist is found by calculating the area under the velocity-time graph.

Step 1: Compute the Areas

1st segment (Triangle, 0 to 5 s):
Base = 5 s, Height = 10 m/s
Area = (1/2) × 5 × 10 = 25 m

2nd segment (Rectangle, 5 to 15 s):
Base = 10 s, Height = 10 m/s
Area = 10 × 10 = 100 m

3rd segment (Triangle, 15 to 30 s):
Base = 15 s, Height = 10 m/s
Area = (1/2) × 15 × 10 = 75 m

Step 2: Total Distance

Total Distance = 25 + 100 + 75 = 200 meters

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