The Problem:
A balloon at a height of 300 m is descending at 10 ms-1 and decelerating at a rate of 0.4 ms-2 How long will it take for the balloon to stop descending, and what will its height be then?

The Problem:
A balloon at a height of 300 m is descending at 10 ms-1 and decelerating at a rate of 0.4 ms-2 How long will it take for the balloon to stop descending, and what will its height be then?
Douglas Quadling Mechanics 1
Exercise 1B Q7
A balloon at a height of 300 m is descending at 10 ms and decelerating at a rate of 0.4 ms 2….
3 October 2023 by alevelmechanics1

Problem Statement
A balloon at a height of 300 m is descending at 10 m/s and decelerating at a rate of 0.4 m/s². How long will it take for the balloon to stop descending, and what will its height be then?
Solution
Given:
- Initial height (h₀) = 300 m
- Initial velocity (u) = 10 m/s (descending)
- Deceleration (a) = -0.4 m/s² (opposes motion)
- Final velocity (v) = 0 m/s (balloon stops descending)
Step 1: Find the Time (t) for the Balloon to Stop Descending
We use the equation of motion:
v = u + a * t
Substitute the values:
0 = 10 + (-0.4) * t 0 = 10 - 0.4t 0.4t = 10 t = 10 / 0.4 t = 25 seconds
Time for the balloon to stop descending = 25 seconds
Step 2: Calculate the Height (h) When the Balloon Stops
We use the equation of motion:
s = u * t + 0.5 * a * t²
Substitute the values:
s = 10 * 25 + 0.5 * (-0.4) * (25)² s = 250 + 0.5 * (-0.4) * 625 s = 250 - 0.2 * 625 s = 250 - 125 s = 125 m
The balloon descends 125 meters before stopping. Therefore, its final height is:
h = h₀ - s h = 300 - 125 h = 175 m
Final height of the balloon = 175 meters
Final Answers:
- Time for the balloon to stop descending = 25 seconds
- Final height of the balloon = 175 meters